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luda... Registered User
Joined: 28 Jan 2003 Location: pittsburgh pa Posts: 231
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Posted: Thu Apr 03, 2003 6:25 pm Post subject: omgomgomg wow |
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yall check this out. follow the directions wow i cant stump it once. http://ebaumsworld.com/mindprobe.html _________________ Remember me? I do =) |
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shockwave Server Admin
Joined: 26 Feb 2003 Location: Drunk in the corner in some Texas bar. Posts: 1970
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Posted: Thu Apr 03, 2003 6:33 pm Post subject: |
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I can read your mind also....
1. Think of a number with 2 digits
2. Subtract from this number its 2 digits
3. Concentrate on this number and dont click anywhere....
Conclusion: The final number is a multiple of 9!!!! _________________
Last edited by shockwave on Thu Apr 03, 2003 6:46 pm; edited 1 time in total |
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Violent Pacifist Registered User
Joined: 29 Dec 2001 Location: Ft. Worth, TX Posts: 1776
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Posted: Thu Apr 03, 2003 6:36 pm Post subject: |
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Yar, it's just some complicated formula. Some people explained how it works exactly in a thread like this before. _________________
We are the music makers, and we are the dreamers of dreams. |
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shockwave Server Admin
Joined: 26 Feb 2003 Location: Drunk in the corner in some Texas bar. Posts: 1970
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Posted: Thu Apr 03, 2003 6:38 pm Post subject: |
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Violent Pacifist wrote: | Yar, it's just some complicated formula. Some people explained how it works exactly in a thread like this before. |
Want the explaination or just accept my answer? _________________
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Mr.Kason Allen Registered User
Joined: 06 Dec 2002 Location: Somewhere over a rainbow Posts: 1002
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Posted: Thu Apr 03, 2003 6:55 pm Post subject: |
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Im not going to explain it shockwave can it took me about 45 seconds to figure after I spotted all of one symbol in a row from 9 diagonally up _________________ Over your dead body! |
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shockwave Server Admin
Joined: 26 Feb 2003 Location: Drunk in the corner in some Texas bar. Posts: 1970
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Posted: Thu Apr 03, 2003 7:16 pm Post subject: |
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Here is another problem for those of you who can answer the last problem:
A man has some number of dollar bills and needs to divide them into seperate but equal groups (to be fair to each) so that he can distribute them to many charities. He tries 2 charities, but finds he has 1 dollar bill left over. Then he tries 3 charities, but has 2 dollar bills left over ...and so on, until he gets to groups of 17, and the dollar bills fit perfectly. How many dollar bills are there? _________________
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Stevo Ville Supporter
Joined: 08 Dec 2002 Location: Orange County Guild: TVR Posts: 9514
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Posted: Thu Apr 03, 2003 11:07 pm Post subject: |
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Shockwave wrote: | Conclusion: The final number is a multiple of 9!!!! |
^^^^^^^^^^^^^
Explained in the simplest way possible! _________________
The Official TVR Website
Fopp
Song of the Week |
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shockwave Server Admin
Joined: 26 Feb 2003 Location: Drunk in the corner in some Texas bar. Posts: 1970
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Posted: Fri Apr 04, 2003 6:48 am Post subject: |
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Stevo wrote: | Shockwave wrote: | Conclusion: The final number is a multiple of 9!!!! |
^^^^^^^^^^^^^
Explained in the simplest way possible! |
Do you actually want the mathematical formula? _________________
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Stevo Ville Supporter
Joined: 08 Dec 2002 Location: Orange County Guild: TVR Posts: 9514
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Posted: Fri Apr 04, 2003 6:35 pm Post subject: |
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Okay, for those of you having trouble understanding this, here is an explanation:
The final answer is always going to be a multiple of nine. For example,
10-1-0=9/9=1
20-2-0=18/9=2
30-3-0=27/9=3
40-4-0=36/9=4
or you can choose any random number like,
47-4-7=36/9=4
99-9-9=81/9=9
As you can see, all of these are evenly divisible by 9, so all the multiples of nine have the same symbols.
X=starting #
y=first digit
n=second digit
t=multiple of 9
X-y-n=t
STARTING#-first digit-second digit=resulting multiple of 9[/i]
In conclusion:The final number will always be a multiple of 9 _________________
The Official TVR Website
Fopp
Song of the Week |
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Gamepro65 Registered User
Joined: 02 Dec 2001
Posts: 710
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Posted: Fri Apr 04, 2003 9:20 pm Post subject: |
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whats with this nine stuff???? all they did was
# - first digit - last digit = symbol rite well (i like being complicated so here goes) they did each number from 99 - 1 (i sware they dumbasses tho for you cant have 99 as a number for ud have to subtract it so thats a waste of space) but they did all of those and found the answer bam put a symbol their and boom their is your answer! _________________
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SanLeo Registered User
Joined: 05 Oct 2002
Posts: 46
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Posted: Sat Apr 05, 2003 4:05 am Post subject: |
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Shockwave wrote: | Here is another problem for those of you who can answer the last problem:
A man has some number of dollar bills and needs to divide them into seperate but equal groups (to be fair to each) so that he can distribute them to many charities. He tries 2 charities, but finds he has 1 dollar bill left over. Then he tries 3 charities, but has 2 dollar bills left over ...and so on, until he gets to groups of 17, and the dollar bills fit perfectly. How many dollar bills are there? |
Give me a harder one. _________________
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luda... Registered User
Joined: 28 Jan 2003 Location: pittsburgh pa Posts: 231
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Posted: Sat Apr 05, 2003 8:56 am Post subject: |
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ohhhhhhhhhhhhhhhhh i c thx _________________ Remember me? I do =) |
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Paddyjack Registered User
Joined: 15 Jan 2002 Location: Québec, Canada Guild: <eVa> Posts: 1722
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Posted: Sat Apr 05, 2003 9:48 am Post subject: |
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Shockwave wrote: | Here is another problem for those of you who can answer the last problem:
A man has some number of dollar bills and needs to divide them into seperate but equal groups (to be fair to each) so that he can distribute them to many charities. He tries 2 charities, but finds he has 1 dollar bill left over. Then he tries 3 charities, but has 2 dollar bills left over ...and so on, until he gets to groups of 17, and the dollar bills fit perfectly. How many dollar bills are there? |
After a very "long" thinking....... 17$ _________________ PJ --- ancient IDIOT with a rusty CROWBAR....
but still SWINGING!
Rock2..... JUST SAY NO!!!!! |
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shockwave Server Admin
Joined: 26 Feb 2003 Location: Drunk in the corner in some Texas bar. Posts: 1970
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Posted: Sat Apr 05, 2003 10:55 am Post subject: |
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Paddyjac-K wrote: |
After a very "long" thinking....... 17$ |
From the word "groups", you can not have just one. _________________
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Paddyjack Registered User
Joined: 15 Jan 2002 Location: Québec, Canada Guild: <eVa> Posts: 1722
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Posted: Sat Apr 05, 2003 11:20 am Post subject: |
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Shockwave wrote: | Paddyjac-K wrote: |
After a very "long" thinking....... 17$ |
From the word "groups", you can not have just one. |
Oh yeah, sorry
119$ then
y: $$$
X: multiply by
y=17x
z=(y-1)/2
a=(y-2)/3
now: a+z=y-3x
thus: (y-2)/3 + (y-1)/2 - y =-3x
(-y-7)/6 = -18x/6
7=x
so: 7*17=119 _________________ PJ --- ancient IDIOT with a rusty CROWBAR....
but still SWINGING!
Rock2..... JUST SAY NO!!!!! |
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